Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
please
Date Posted: 4 years ago
Views: 240
log₂₇ 3 = log 3/log 27
= log 3/3log 3
= 1/3
log₆₄ [ log₂ (2x+3)] = 1/3
=> log₂ (2x+3) = 64^(1/3) = 4
=> log₂ (2x+3) = 4
=> 2x+3 = 2⁴ = 16
=> 2x+3 = 16
=> x = 13/2
.
= log 3/3log 3
= 1/3
log₆₄ [ log₂ (2x+3)] = 1/3
=> log₂ (2x+3) = 64^(1/3) = 4
=> log₂ (2x+3) = 4
=> 2x+3 = 2⁴ = 16
=> 2x+3 = 16
=> x = 13/2
.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
For log 27 3, we use a change of base to base 2 to simply this expression. Or, if you can recognise that 3 is the cube root of 27, you can convert the 3 to the cube root of 27 before evaluating this logarithm to 1/3.
We then convert each log into index form from the outermost log to the innermost log if there are several logs arranged in a row.
We then convert each log into index form from the outermost log to the innermost log if there are several logs arranged in a row.
Date Posted:
4 years ago
360 Tutoring Program