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Question
primary 6 | Maths
| Fractions
One Answer Below
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Pls help
Date Posted: 4 years ago
Views: 272
1/13
= 0.076923 . . .
(*use calculator or long division )
the 6 digits that repeat are
0 , 7 , 6 , 9 , 2 , 3
sum = 0+7+6+9+2+3 = 27
2019/6 =336.5
or 336 sets and remaining 3 digits, that is 0 , 7 & 6
sum of 1 set =27
sum of 336 sets =27 x336 = 9072
add the remaining 3 digits = 9072+13
= 9085
.
.
.
= 0.076923 . . .
(*use calculator or long division )
the 6 digits that repeat are
0 , 7 , 6 , 9 , 2 , 3
sum = 0+7+6+9+2+3 = 27
2019/6 =336.5
or 336 sets and remaining 3 digits, that is 0 , 7 & 6
sum of 1 set =27
sum of 336 sets =27 x336 = 9072
add the remaining 3 digits = 9072+13
= 9085
.
.
.
See 1 Answer
done
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Use calculator to find 1/13 to see the repeating digits first.
Date Posted:
4 years ago
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