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secondary 4 | A Maths
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The answer is supposed to be x=63.4°, 116.6°, 243.4°, 296.6°. I get that there is another method that can solve this qns, however i dont know why my method does not achieve all the solutions..
the reason u din get all the ans. is bcos u rejected the ans.
cos x = -0.44721
this means u forgo the angles in the 2nd quad & and 3rd quad.
=> x = 180 - 63.4 or 180+ 63.4
= x = 116.6° or 243.4°
so long u dun reject the negative trigo values, if u ever see any, u shld b doing fine.
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