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secondary 4 | A Maths
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A math
Date Posted: 7 years ago
Views: 458
i) Draw a perpendicular drop from B to AO (call the line on AO 'x'), and draw a horizontal on C to that vertical line. You now have 2 right angle triangles.
You can see that in the small triangle, the angle CBX is theta degrees. The length of AX is 12*cos(theta), and the length OX is the same as 5sin(theta)
ii) You can just simply use the R formula to get that expression in those terms.
iii) You can see that at maximum OA, R must be multiplied by 1 (largest value of sine is 1). Therefore sin(theta + alpha) has to be 1. You can work backwards to find the value of theta.
iv) Just substitute OA to be 8 = Rsin(theta+alpha). Simple trigonometry will get you theta at 8cm.
Go try it out! Hope it helps
You can see that in the small triangle, the angle CBX is theta degrees. The length of AX is 12*cos(theta), and the length OX is the same as 5sin(theta)
ii) You can just simply use the R formula to get that expression in those terms.
iii) You can see that at maximum OA, R must be multiplied by 1 (largest value of sine is 1). Therefore sin(theta + alpha) has to be 1. You can work backwards to find the value of theta.
iv) Just substitute OA to be 8 = Rsin(theta+alpha). Simple trigonometry will get you theta at 8cm.
Go try it out! Hope it helps
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