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Secondary 1 | Maths
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Date Posted: 4 years ago
Views: 269
54=2x3³
378= 2ⅹ3³ⅹ7
Therefore, smallest number for k = 7.
Hope this helps
378= 2ⅹ3³ⅹ7
Therefore, smallest number for k = 7.
Hope this helps
See 1 Answer
54=2x3³
378= 2ⅹ3³ⅹ7
Therefore, smallest number for k = 7.
Hope this helps
378= 2ⅹ3³ⅹ7
Therefore, smallest number for k = 7.
Hope this helps
Why 7 is the smallest no
54=2ⅹ3³
378= (2ⅹ3³)×7
Compared 2 prime factor, 54 is 2ⅹ 3 ³
The other number should be 7.
378= (2ⅹ3³)×7
Compared 2 prime factor, 54 is 2ⅹ 3 ³
The other number should be 7.
How about what is the smallest value of n such that the lcm is n and 6 is 24
For this LCM....
6 = 2 × 3
24 = 2³ × 3
My idea of finding n is look for different of product of prime factor...
The different here is 2 and 2³ so for LCM, we always look for highest prime notation. i.e 2³ for this case. Answer is 8.
As for 54 = 2 × 3³
378 = 2 × 3³ × 7
Compared the different, here the different is 7, so n=7. 7¹ is highest prime notation for this case.
Sorry for late reply as i face difficulty to explain as well.
Hope this helps.
6 = 2 × 3
24 = 2³ × 3
My idea of finding n is look for different of product of prime factor...
The different here is 2 and 2³ so for LCM, we always look for highest prime notation. i.e 2³ for this case. Answer is 8.
As for 54 = 2 × 3³
378 = 2 × 3³ × 7
Compared the different, here the different is 7, so n=7. 7¹ is highest prime notation for this case.
Sorry for late reply as i face difficulty to explain as well.
Hope this helps.
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