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secondary 3 | E Maths
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Starseed
Starseed

secondary 3 chevron_right E Maths chevron_right Singapore

Hi! I need help for this question, thank you for helping :)

Date Posted: 4 years ago
Views: 207
snell
Snell
4 years ago
(a)
at start, ball at top of building
=> t = 0

h = 50+10t-5t² = 50

height = 50m


(b)
at top of building again,
=> 50+10t-5t² = 50
=> 5t² - 10t = 0
=> t(t - 10) = 0
=> t = 0 or t = 10 s

at t = 10 s



(c)
reach ground => h = 0 m
=> 50+10t-5t² = 0
=> t² - 2t - 10 = 0
(use formula)
=> t = -2.32 s (rejected) or
=> t = 4.32 s


(d)
at h = 30 m
=> 50+10t-5t² = 30
=> t² - 2t - 4 = 0
(use formula)
=> t = -1.24 s (rejected) or
=> t = 3.24 s



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Starseed
Starseed
4 years ago
@snell thanks for helping me :)
snell
Snell
4 years ago
np

hope u understand

.

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Hi it's been answered by snell thanks :)
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Starseed
Starseed's answer
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