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secondary 3 | A Maths
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pls help me for qn 3
Date Posted: 7 years ago
Views: 757
This is a topic about b^2 - 4ac.
(a)
You want some line to be a tangent to some quadratic curve.
This means that you want line = curve to have exactly one solution (because a tangent touches a quadratic equation at exactly one point).
So set the them to be equal, shift everything to one side, then set b^2 - 4ac = 0 to find p.
(b) A graph being always positive means it doesn't intersect the x -axis, which means there's is no solution for graph = 0.
So set b^2 -4ac < 0 to find k.
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Solution will be up later.
(a)
You want some line to be a tangent to some quadratic curve.
This means that you want line = curve to have exactly one solution (because a tangent touches a quadratic equation at exactly one point).
So set the them to be equal, shift everything to one side, then set b^2 - 4ac = 0 to find p.
(b) A graph being always positive means it doesn't intersect the x -axis, which means there's is no solution for graph = 0.
So set b^2 -4ac < 0 to find k.
---
Solution will be up later.
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Date Posted:
7 years ago
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