Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Hi! I am doing a question on differentiation and I’m confused as to how to arrive at the last step from the second last step. Thank you so much if you helped :)
Date Posted: 4 years ago
Views: 302
We simply take out the common terms just like we normally do in standard common term factorisation.
do u mean this?
(x - 5)⁷ [4(x + 3)³] + (x + 3)⁴ [7(x - 5)³]
= (x - 5)⁶ (x + 3)³ [ 4(x - 5) ]
+ (x + 3)³ (x - 5)⁶ [7(x + 3)]
= (x - 5)⁶ (x + 3)³ (4x - 20)
+ (x + 3)³ (x - 5)⁶ (7x + 21)
= (x - 5)⁶ (x + 3)³ (4x - 20 + 7x + 21)
= (x - 5)⁶ (x + 3)³ (11x + 1)
.
.
.
(x - 5)⁷ [4(x + 3)³] + (x + 3)⁴ [7(x - 5)³]
= (x - 5)⁶ (x + 3)³ [ 4(x - 5) ]
+ (x + 3)³ (x - 5)⁶ [7(x + 3)]
= (x - 5)⁶ (x + 3)³ (4x - 20)
+ (x + 3)³ (x - 5)⁶ (7x + 21)
= (x - 5)⁶ (x + 3)³ (4x - 20 + 7x + 21)
= (x - 5)⁶ (x + 3)³ (11x + 1)
.
.
.
thank you guys
See 2 Answers
You missed the point fully. We are supposed to factorise the final expression further to the simplest form.
Unless the picture did not load fully.
Unless the picture did not load fully.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
It’s basically your standard factorisation techniques, except that the expressions are more complicated this time.
Date Posted:
4 years ago
Thank you!
360 Tutoring Program