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Question
primary 5 | Maths
| Whole Numbers
2 Answers Below
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Date Posted: 4 years ago
Views: 220
7 table 12 chair 988
2 table 3 chair 263
Since 2 tables and 3 chairs cost a total of $263, 4 sets of these (8 tables and 12 chairs) will cost $263 x 4 = $1052.
So,
8 tables + 12 chairs cost $1052
7 tables + 12 chairs cost $988
The difference in these is just 1 table, which costs $64.
Then 2 tables cost $128, so 3 chairs cost $263 - $128 = $135.
1 chair costs $45.
Cost of 2 tables and 1 chair
= $128 + $45
= $173
2 table 3 chair 263
Since 2 tables and 3 chairs cost a total of $263, 4 sets of these (8 tables and 12 chairs) will cost $263 x 4 = $1052.
So,
8 tables + 12 chairs cost $1052
7 tables + 12 chairs cost $988
The difference in these is just 1 table, which costs $64.
Then 2 tables cost $128, so 3 chairs cost $263 - $128 = $135.
1 chair costs $45.
Cost of 2 tables and 1 chair
= $128 + $45
= $173
Thank you!
See 2 Answers
done
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clear
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I hope you understand the method I used
Date Posted:
4 years ago
Thank you
Thank you
Thank you!
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