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primary 5 | Maths
| Fractions
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Anyone please?
Date Posted: 4 years ago
Views: 256
total: 90u
J: 20u
Miche: 800 mL
remainder: 70u - 800 (<= 10/10)
Micha: 21u - 240 (<= 3/10)
left: 49u - 560 (for K)
1/3 of Micha = 200 mL
3/3 of Micha = 600 mL
21u - 240 = 600
1u = 40
90u = 3600
at first 3600 mL
.
.
.
J: 20u
Miche: 800 mL
remainder: 70u - 800 (<= 10/10)
Micha: 21u - 240 (<= 3/10)
left: 49u - 560 (for K)
1/3 of Micha = 200 mL
3/3 of Micha = 600 mL
21u - 240 = 600
1u = 40
90u = 3600
at first 3600 mL
.
.
.
I thought thatthe answer is 4500ml
the answer should be 3600ml. Snell can explain how you get the 21 units? (On michael’s portion?) and the 240 comes from where?
ok
after giving Michelle
the remainder is 70u-800
Michael takes 3/10 of remainder
so
3/10 x (70u-800)
= 3/10 x70u - 3/10 x 800
= 21u - 240
after giving Michelle
the remainder is 70u-800
Michael takes 3/10 of remainder
so
3/10 x (70u-800)
= 3/10 x70u - 3/10 x 800
= 21u - 240
Thank you!
See 1 Answer
done
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clear
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So sorry it is messy
Date Posted:
4 years ago
let's assume ur ans: 4500mL is correct
& we work forward according to qn to check ans, k?
total is 4500 mL
give Josh: 2/9 x 4500 = 1000 mL
left: 3500mL
give Michelle: 800mL
left: 3500-800 = 2700mL
give Michael: 3/10 x 2700mL = 810mL
but this contradict ur own calculation of Michael getting 600mL
so do u agree that 4500mL is incorrect ans?
& we work forward according to qn to check ans, k?
total is 4500 mL
give Josh: 2/9 x 4500 = 1000 mL
left: 3500mL
give Michelle: 800mL
left: 3500-800 = 2700mL
give Michael: 3/10 x 2700mL = 810mL
but this contradict ur own calculation of Michael getting 600mL
so do u agree that 4500mL is incorrect ans?
No! Finally l understood! Thank you very much
I mean YES
Last step is incorrect.
900 x 4 = 3600ml. (Ans)
900 x 4 = 3600ml. (Ans)
Thanks!
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