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Secondary 1 | Maths
2 Answers Below
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Someone help with these three questions please!
Date Posted: 4 years ago
Views: 405
Qn 5
1584/11 = 144
144/2 = 72
72/2 = 36
36/2= 18
18/2 = 9
9/3 = 3
3/3 = 1
1584 = 2^4 x 3^2 x 11
Qn 6
Similar to Qn 5
Qn 7
p =1
1 x (1 + 36) = 37
Not sure what other methods can be used instead of guessing.
1584/11 = 144
144/2 = 72
72/2 = 36
36/2= 18
18/2 = 9
9/3 = 3
3/3 = 1
1584 = 2^4 x 3^2 x 11
Qn 6
Similar to Qn 5
Qn 7
p =1
1 x (1 + 36) = 37
Not sure what other methods can be used instead of guessing.
See 2 Answers
done
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Do let me know if you need further clarification!
Date Posted:
4 years ago
Qn 6 is similar to Qn 5!
Qn 7. Hmm I think you can only do trial and error. The biggest hint is the word ‘whole number’ so you just sub in values like p=1, p=2, p=3 etc etc until you get a prime number. So when you try, p=1 gives a prime number 37! The answer would be 37 then.
Qn 7. Hmm I think you can only do trial and error. The biggest hint is the word ‘whole number’ so you just sub in values like p=1, p=2, p=3 etc etc until you get a prime number. So when you try, p=1 gives a prime number 37! The answer would be 37 then.
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