Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 1 | H2 Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
would appreciate if someone could help me!
Date Posted: 4 years ago
Views: 250
Both c and sin c increase as x increases from 0 to pi/2.
Sin 0 is 0, while sin pi/2 is 1.
So the minimum limit is 0, while the maximum limit is 1 + pi/2.
The function c + sin c is also continuous, taking on all possible values of y from 0 to 1 + pi/2, so there must be some point in between 0 and pi/2 in which c + sin c = 1.
Sin 0 is 0, while sin pi/2 is 1.
So the minimum limit is 0, while the maximum limit is 1 + pi/2.
The function c + sin c is also continuous, taking on all possible values of y from 0 to 1 + pi/2, so there must be some point in between 0 and pi/2 in which c + sin c = 1.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Use GC to graph the equation and find C
Since C=0.511, which is within the range, it is proven.
Since C=0.511, which is within the range, it is proven.
Date Posted:
4 years ago
360 Tutoring Program