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secondary 4 | A Maths
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Pls help with this 2 qns as soon as possible
Date Posted: 4 years ago
Views: 179
Good afternoon Tarah! I will have a look at this by 4 am.
dy/dx
= 2√(5x-9) + (2x+3) . ½ . 5/√(5x-9)
= (20x - 36 + 10x + 15)/[2√(5x-9)]
= (30x - 21)/[2√(5x-9)]
k=30
= 2√(5x-9) + (2x+3) . ½ . 5/√(5x-9)
= (20x - 36 + 10x + 15)/[2√(5x-9)]
= (30x - 21)/[2√(5x-9)]
k=30
y = (x+1)/√(1-2x)
dy/dx
= [√(1-2x) - (x+1) . ½ . -2/√(1-2x)]/(1-2x)
= [(1-2x) + x + 1]/√(1-2x)³
= (-x + 2)/√(1-2x)³
n = 0
dy/dx
= [√(1-2x) - (x+1) . ½ . -2/√(1-2x)]/(1-2x)
= [(1-2x) + x + 1]/√(1-2x)³
= (-x + 2)/√(1-2x)³
n = 0
See 2 Answers
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First part
Date Posted:
4 years ago
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Second part
Date Posted:
4 years ago
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