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secondary 3 | A Maths
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can someone teach me how to solve questions like q8 and 9,like whats the method and how to do it
Date Posted: 4 years ago
Views: 187
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The idea for Q8 is something like this. There are other methods too, but this one is the easiest to consider.
Hold on for Q9.
Hold on for Q9.
Date Posted:
4 years ago
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Q9 uses a very similar approach.
Also, the remainder will have a degree equal to at most 1 degree lower than the degree of the divisor, for your information. For example, in this case the divisor x2 - 1 has a degree of 2, so the degree of the remainder is at most 1 (most of the time, the degree of the remainder is exactly 1 lower than the degree of the divisor).
Also, the remainder will have a degree equal to at most 1 degree lower than the degree of the divisor, for your information. For example, in this case the divisor x2 - 1 has a degree of 2, so the degree of the remainder is at most 1 (most of the time, the degree of the remainder is exactly 1 lower than the degree of the divisor).
Date Posted:
4 years ago
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