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Question
primary 6 | Maths
| Geometry
2 Answers Below
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Date Posted: 4 years ago
Views: 290
5.
since O is centre,
OX = OY = OZ = radius
so
OX = OY = OZ = WX
angle WXO = 180-19-19 = 142 deg
*triangle WXO is isosceles
angle YXO = 180-142 = 38 deg
*triangle OXY is isosceles
angle XOY = 180-38-38 = 104 deg
angle YOZ = 180-104-19 = 57 deg
angle YOZ = (180-57)/2 = 61.5 deg
*triangle YOZ is isosceles
* * *
since O is centre,
OX = OY = OZ = radius
so
OX = OY = OZ = WX
angle WXO = 180-19-19 = 142 deg
*triangle WXO is isosceles
angle YXO = 180-142 = 38 deg
*triangle OXY is isosceles
angle XOY = 180-38-38 = 104 deg
angle YOZ = 180-104-19 = 57 deg
angle YOZ = (180-57)/2 = 61.5 deg
*triangle YOZ is isosceles
* * *
6.
FDE = 30 deg
FED = 136 deg
angle p = 180- 136 - 30 = 14 deg
4q = 180 - p = 166 deg
angle q = 41.5 deg
.
.
.
FDE = 30 deg
FED = 136 deg
angle p = 180- 136 - 30 = 14 deg
4q = 180 - p = 166 deg
angle q = 41.5 deg
.
.
.
See 2 Answers
done
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use concept of radius since o is centre of circle
Date Posted:
4 years ago
Thanks!
done
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use concept of angles on straight lines = 180°
Date Posted:
4 years ago
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