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secondary 4 | A Maths
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Date Posted: 4 years ago
Views: 178
2 + b = a
dy/dx = -ab(2 + bx)⁻²
-ab(2 + b)⁻² = ⅗
-5ab = 3(2 + b)²
-5b(2 + b) = 3(2 + b)²
(6 + 3b -5b)(2 + b) = 0
(6 - 2b)(2 + b) = 0
b = 3 or -2 (rejected)
a = 5
y = 5/(2 + 3x)
dy/dx = -ab(2 + bx)⁻²
-ab(2 + b)⁻² = ⅗
-5ab = 3(2 + b)²
-5b(2 + b) = 3(2 + b)²
(6 + 3b -5b)(2 + b) = 0
(6 - 2b)(2 + b) = 0
b = 3 or -2 (rejected)
a = 5
y = 5/(2 + 3x)
See 1 Answer
done
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clear
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Good evening Tarah! Here are my workings for this question.
Date Posted:
4 years ago
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