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secondary 4 | A Maths
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Very confused on how to solve part 2. Would appreciate detailed worked solution. Thank you!
Date Posted: 4 years ago
Views: 205
let P = sin x + cos ½x &
Q = 1 - cos x + sin ½x
(ii)
qn becomes P/Q = √3
&
P/Q = 1/(Q/P)
= {(1 - cos x + sin ½x)/(sin x + cos ½x)}⁻¹
using part (i),
P/Q
= [ tan ½x ]⁻¹
eqn becomes
[ tan ½x ]⁻¹ = √3
tan ½x = 1/√3
* u cont. here
Q = 1 - cos x + sin ½x
(ii)
qn becomes P/Q = √3
&
P/Q = 1/(Q/P)
= {(1 - cos x + sin ½x)/(sin x + cos ½x)}⁻¹
using part (i),
P/Q
= [ tan ½x ]⁻¹
eqn becomes
[ tan ½x ]⁻¹ = √3
tan ½x = 1/√3
* u cont. here
Good evening Cheryl! I will have a look at this by 4 am if no one has done them yet by then.
See 1 Answer
done
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clear
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Good evening Cheryl! We look out for similarities between the given question and our proven identity so that we can rewrite the given question in simpler terms using the identity provided.
Date Posted:
4 years ago
Thank you!!!!
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