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secondary 3 | E Maths
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JL
JL

secondary 3 chevron_right E Maths chevron_right Singapore

NA Math, couldn’t managed to get the same answer as the book given... hopes there anyone out there able to teach me step by step thank you

Date Posted: 4 years ago
Views: 757
snell
Snell
4 years ago
(c)
(-5mn³)³ = (-5)³ (m)³ (n³)³
= -125 x m³ x n⁹

(-5mn³)³ (6m²n⁹)
= -125 x m³ x n⁹ x 6 x m² x n⁹
= -750 x m⁵ x n¹⁸


(-3m²n⁴)² = (-2)² (m²)² (n⁴)²
= 4 x m⁴ x n⁸


(-5mn³)³ (6m²n⁹)/(-3m²n⁴)²
= (-750 x m⁵ x n¹⁸)/(4 x m⁴ x n⁸)
= (-375 x m x n¹⁰)/2
= ½(-375 x m x n¹⁰)

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Johnson Poon
Johnson Poon's answer
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