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secondary 4 | A Maths
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secondary 4 chevron_right A Maths chevron_right Singapore

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Date Posted: 4 years ago
Views: 241
snell
Snell
4 years ago
let angle θ = cos⁻¹ (-1/5)
cos θ = -1/5
(-ve , θ in 2nd or 3rd quad)

cos θ = -1/5
this means
adj = -1
hyp = 5
opp = √[ 5² - (-1)² ] = √24

so
sin θ = opp/hyp = √24/5

(a)
sin [ cos⁻¹ (-1/5) ]
= sin θ
= √24/5
MM
MM
4 years ago
Thank you
Eric Nicholas K
Eric Nicholas K
4 years ago
Will look at this question by 4 am
snell
Snell
4 years ago
(b)
let angle θ = sin⁻¹ (-2/3)
sin θ = -2/3
(-ve , θ in 3rd or 4th quad)

sin θ = -2/3
this means
opp = -2
hyp = 3
adj = √[ 3² - (-2)² ] = √5

so
tan θ = opp/adj = -2/√5

(b)
tan [ sin⁻¹ (-2/3) ]
= tan θ
= -2/√5

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
For the first one
MM
MM
4 years ago
Thank you
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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
Second one, to be continued
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Eric Nicholas K
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