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secondary 3 | A Maths
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Date Posted: 4 years ago
Views: 602
2x² + xy - y² = 4x - 2y = 26
=>
2x² + xy - y² = 26 . . . [1]
=>
4x - 2y = 26
2x - y = 13
y = 2x - 13 . . . [2]
2x² + x(2x - 13) - (2x - 13)² = 26
2x² + 2x² - 13x - 4x² + 52x - 169 = 26
x = 5
y = -3
.
.
.
=>
2x² + xy - y² = 26 . . . [1]
=>
4x - 2y = 26
2x - y = 13
y = 2x - 13 . . . [2]
2x² + x(2x - 13) - (2x - 13)² = 26
2x² + 2x² - 13x - 4x² + 52x - 169 = 26
x = 5
y = -3
.
.
.
See 1 Answer
done
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Solve the 2 eqn:
4x-2y = 26
and
2x^2+xy-y^2 = 26
4x-2y = 26
and
2x^2+xy-y^2 = 26
Date Posted:
4 years ago
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