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secondary 3 | A Maths
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I'm not sure how to solve this question, please help! Thank You!
Date Posted: 4 years ago
Views: 294
⅒(x² - x) + c
complete the sq to find min. value,
= ⅒(x² - x + ½² - ½²) + c
= ⅒(x - ½)² - 1/40 + c
min. value is - 1/40 + c
given min. value is -3
- 1/40 + c = -3
=> c = -119/40
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complete the sq to find min. value,
= ⅒(x² - x + ½² - ½²) + c
= ⅒(x - ½)² - 1/40 + c
min. value is - 1/40 + c
given min. value is -3
- 1/40 + c = -3
=> c = -119/40
.
.
.
See 1 Answer
done
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clear
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All because the lowest value of x2 - x is not zero, the value of c will not be the same as the lowest value of the entire function.
Date Posted:
4 years ago
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