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secondary 2 | Maths
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Date Posted: 4 years ago
Views: 241
given y ∝ x²
=> y = kx² , where k is a const.
when y = a
=> a = kx²
=> k = a/x²
when x is doubled, say, x = 2x ,
=> y = k(2x)²
=> y = k(4x²)
=> y = (a/x²)(4x²) [ subst. k = a/x² ]
=> y = 4a
.
.
.
=> y = kx² , where k is a const.
when y = a
=> a = kx²
=> k = a/x²
when x is doubled, say, x = 2x ,
=> y = k(2x)²
=> y = k(4x²)
=> y = (a/x²)(4x²) [ subst. k = a/x² ]
=> y = 4a
.
.
.
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