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secondary 4 | A Maths
4 Answers Below
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very confused on how to solve these questions. Would appreciate detailed worked solution. Thanks!
Date Posted: 4 years ago
Views: 515
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Good evening Cheryl! Here are my workings for sin 3A.
Date Posted:
4 years ago
Thank you!!
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Good evening Cheryl! Here are my workings for cos 3A.
Date Posted:
4 years ago
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Good evening Cheryl! Here are my workings for tan 3A.
Alternatively, we can express tan 3A as sin 3A divided by cos 3A, but this is a much harder approach.
Alternatively, we can express tan 3A as sin 3A divided by cos 3A, but this is a much harder approach.
Date Posted:
4 years ago
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Good evening Cheryl! Here are my workings for the remaining questions.
For Q4c, I have tried really hard to prove the final identity but I just cannot seem to obtain the final answer. I also used random numbers into the given identity and both sides of the equation do not hold. But I may be wrong somewhere in my workings.
For Q4c, I have tried really hard to prove the final identity but I just cannot seem to obtain the final answer. I also used random numbers into the given identity and both sides of the equation do not hold. But I may be wrong somewhere in my workings.
Date Posted:
4 years ago
Thank you! I’ll try from there!!!
For question Q4c, there is mistake in the given "identity".
To check, can substitute some angles and see if LHS = RHS.
From substituting different angles like x=60 degrees and x=30 degrees, it looks like the mistake is the sign between the 2 terms on the LHS. It should be "+" instead of "-".
To check, can substitute some angles and see if LHS = RHS.
From substituting different angles like x=60 degrees and x=30 degrees, it looks like the mistake is the sign between the 2 terms on the LHS. It should be "+" instead of "-".
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