Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Help with 5d please
Date Posted: 4 years ago
Views: 186
d/dx [sin2 (3x2) - cos (1/x)]
= d/dx [(sin 3x2)2 - cos (1/x)
= 2 (sin 3x2)^1 times differentiate of sin 3x 2 - (- sin 1/x) times differentiate 1/x
And so on. Two chain rules needed on the sin2 3x2.
Will look at this by 4 am if no one has done them yet.
= d/dx [(sin 3x2)2 - cos (1/x)
= 2 (sin 3x2)^1 times differentiate of sin 3x 2 - (- sin 1/x) times differentiate 1/x
And so on. Two chain rules needed on the sin2 3x2.
Will look at this by 4 am if no one has done them yet.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
The chain rule will be applied at least twice for expressions such as (sin f(x))^n.
There is no need to do the double angle formula to simplify the final expression.
There is no need to do the double angle formula to simplify the final expression.
Date Posted:
4 years ago
360 Tutoring Program