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secondary 3 | A Maths
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Charles
Charles

secondary 3 chevron_right A Maths chevron_right Singapore

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Date Posted: 4 years ago
Views: 232

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Wai Mun
Wai Mun's answer
128 answers (A Helpful Person)
1st
Hopefully this helps
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Krystal Ng
Krystal Ng's answer
2 answers (Tutor Details)
Firstly, find the gradient of the line.
Then, find the equation of the line using Y=mX+C, where Y=1/y and X=x^2
From there, make y the subject.