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secondary 4 | E Maths
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Date Posted: 5 years ago
Views: 252
-a² - 2ab - b²
= -(a² + 2ab + b²)
= -(a + b)²
(a+b)⁴ = [(a + b)²]²
qn
= [(a + b)²]² - (a + b)² - 240
let A = (a + b)²
qn
= A² - A - 240
= (A - 16)(A + 15)
since A = (a + b)² ;
(A - 16)(A + 15)
= [(a + b)² - 16][(a + b)² + 15]
.
.
.
= -(a² + 2ab + b²)
= -(a + b)²
(a+b)⁴ = [(a + b)²]²
qn
= [(a + b)²]² - (a + b)² - 240
let A = (a + b)²
qn
= A² - A - 240
= (A - 16)(A + 15)
since A = (a + b)² ;
(A - 16)(A + 15)
= [(a + b)² - 16][(a + b)² + 15]
.
.
.
See 1 Answer
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2 Upvotes
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We have to do several rounds of factorisations for such questions. Substitutions for the sum a + b and its square can help us visualise the expression better.
Date Posted:
5 years ago
Thank you
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