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Question
secondary 3 | E Maths
2 Answers Below
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Date Posted: 4 years ago
Views: 574
this is taught in A maths as alternate segment theorem.
from alternate segment theorem …
angle BAT = angle BPA
angle PAN = angle PBA
since E maths students do not learn this theorem, have to show it slightly longer way using basics.
angle x = 90 - angleOAB …. [radius tangent perpend.]
=90-(180-angleAOB)/2 ….[OAB isosceles triangle]
=90-90+(1/2)angleAOB
=angle APB ……... [angle centre 2x angle circumf.]
=40
from alternate segment theorem …
angle BAT = angle BPA
angle PAN = angle PBA
since E maths students do not learn this theorem, have to show it slightly longer way using basics.
angle x = 90 - angleOAB …. [radius tangent perpend.]
=90-(180-angleAOB)/2 ….[OAB isosceles triangle]
=90-90+(1/2)angleAOB
=angle APB ……... [angle centre 2x angle circumf.]
=40
See 2 Answers
Draw lines from O to A and O to B then try to use properties of circles
done
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clear
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also known as tangent-chord theorem
Date Posted:
4 years ago
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