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Question
secondary 3 | A Maths
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halp
Date Posted: 4 years ago
Views: 712
Seen, later if no one has done them yet
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Part a
Date Posted:
4 years ago
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I hope you can understand :)
Date Posted:
4 years ago
0 < m < 2 would not work, since the line y = mx passes through (0, 0) for sure regardless of m, so this is taken to be the reference point. Any upsloping line drawn passing (0, 0) will not coincide with the downsloping part of the modulus graph.
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Here
Date Posted:
4 years ago
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Impt parts in red
Date Posted:
4 years ago
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Impt
Parts in red
Parts in red
Date Posted:
4 years ago
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