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Question
secondary 3 | A Maths
2 Answers Below
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logarithm
Date Posted: 4 years ago
Views: 334
(a)
(x² - 10)/(2x+5) = 1
.
.
.
x = 3 or -5
.
(b)
log 2/log x + (log 2/log x)(log y/log 2) +3 =0
.
.
.
log 2y/log x = -3
.
.
.
y = 1/(2x³)
.
(x² - 10)/(2x+5) = 1
.
.
.
x = 3 or -5
.
(b)
log 2/log x + (log 2/log x)(log y/log 2) +3 =0
.
.
.
log 2y/log x = -3
.
.
.
y = 1/(2x³)
.
See 2 Answers
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Something like this would be good.
Date Posted:
4 years ago
done
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epic boomer moment
Date Posted:
4 years ago
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