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secondary 4 | Physics
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I'm stuck on this question, need your help. Thanks in advance!
(i) specific heat capacity of water
(ii) specific heat capacity of ice
(iii) specific latent heat of fusion of water
i m assuming my set of values,
so may be a slight difference from the qn
heat lost
= 1 x 4200 x 20
= 84 000
heat gain
= M x 2100 x 20 + (M-m) x 336 000
= 378 000 M - 336 000 m
84 000
= 378 000 M - 336 000 m
m = 1.125 M - 0.25
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See 2 Answers
Qwerty, you should use the values for the specific heat capacity and specific latent heat provided by your teacher or the syllabus (if the syllabus does quote them).