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secondary 4 | Physics
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qwerty
Qwerty

secondary 4 chevron_right Physics chevron_right Singapore

I'm stuck on this question, need your help. Thanks in advance!

Date Posted: 5 years ago
Views: 515
snell
Snell
5 years ago
u din provide the following:
(i) specific heat capacity of water
(ii) specific heat capacity of ice
(iii) specific latent heat of fusion of water

i m assuming my set of values,
so may be a slight difference from the qn


heat lost
= 1 x 4200 x 20
= 84 000

heat gain
= M x 2100 x 20 + (M-m) x 336 000
= 378 000 M - 336 000 m



84 000
= 378 000 M - 336 000 m


m = 1.125 M - 0.25

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
My answer is different from the given answer.
snell
Snell
5 years ago
shld use specific heat capacity of ice for M
Eric Nicholas K
Eric Nicholas K
5 years ago
Right...
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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
Updated. Credit to Snell for pointing out my error.

Qwerty, you should use the values for the specific heat capacity and specific latent heat provided by your teacher or the syllabus (if the syllabus does quote them).