Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Hi, I need help on this A maths question. Appreciate if someone could advise me:) Thanks !
Date Posted: 4 years ago
Views: 719
Good evening Candice! Whenever we do a quadratic equation with integral coefficients, our roots will be in the form a +- b sqrt c, whole thing divided by a number. There is a symmetry involved. Thus, if one root is 2 - sqrt 3, the other has to be 2 + sqrt 3. With the roots provided in the question, we cannot obtain a quadratic equation with rational coefficients. I will write this up later.
The sum of the two roots may have gotten away with it (being an integer 3) but the product of roots fails to escape. (being sqrt 3 - 1). No two rational numbers multiply or divide to sqrt 3 - 1.
Thank you so much for your prompt advice :)Mr Eric. Your feedback is crystal clear and helpful. Your comments bring instant light to the question I have and I can understand instantly after reading your clear explanation. Once again, thanks a lot!
See 2 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Good evening Candice! Something like this would be good. I will be writing up additional stuff for this question in a moment.
Date Posted:
4 years ago
Thanks Mr Eric. Really appreciate your additional effort to further explain to me :))
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
A little more about the properties of such equations. The two roots must be conjugates of each other because this is the only case where the sum of the two roots (ie the sum of two conjugates) and the product of the two roots (ie the product of two conjugates) are rational numbers.
Date Posted:
4 years ago
thank you so much !
360 Tutoring Program