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secondary 2 | Maths
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how to solve this pair of simultaneous equation using elimination method??
Date Posted: 4 years ago
Views: 232
Observe that x/3 is twice of x/6 and 2y/3 is twice of y/3.
You can multiply one equation by 2. One of the variables will be the same. Then we subtract both equations.
You can multiply one equation by 2. One of the variables will be the same. Then we subtract both equations.
Multiplying the second equation by 2,
x/6 + 4y/3 = 8
The first equation is
x/6 + y/3 = 4
Subtracting both equations,
(x/6 + 4y/3) - (x/6 + y/3) = 8 - 4
3y/3 = 4
y = 4
Putting this into the first equation,
x/6 + 4/3 = 4
x/6 = 8/3
x = 48/3
x = 16
x/6 + 4y/3 = 8
The first equation is
x/6 + y/3 = 4
Subtracting both equations,
(x/6 + 4y/3) - (x/6 + y/3) = 8 - 4
3y/3 = 4
y = 4
Putting this into the first equation,
x/6 + 4/3 = 4
x/6 = 8/3
x = 48/3
x = 16
Even nicer is to let a = x/12 and b = y/3 so that you will get the equations
a + 2b = 4
2a + b = 4
And you can proceed from there.
a + 2b = 4
2a + b = 4
And you can proceed from there.
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Hope this helps
Date Posted:
4 years ago
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