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Question
primary 5 | Maths
| Rate & Ratio
One Answer Below
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$64 for 5 plates and 4 bowls
If 5 plates and 4 bowls cost $64, then three sets of those (15 plates and 12 bowls) cost $192.
Let’s look at the scenario again.
$192 for 15 plates and 12 bowls
$186 for 15 plates and 11 bowls
The difference in this is just a single bowl for $6.
Number of bowls which can be bought with $250
= $250/$6, rounded down
= 41 (remainder 4) rounded down
= 41
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