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secondary 4 | A Maths
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help me pls
Date Posted: 4 years ago
Views: 320
You're on the right track. Length of ED is 2 * sqrt(3), as you have written.
Let angle CAB be theta. Tangent theta is thus the ratio of length BC and length AB. Length AB is 3 * sqrt(3) and length BC is 2, as you wrote. Thus, theta is tangent inverse of 2 / (3 * sqrt(3)). I believe you're stuck here as you found the answer to be 30 - tangent inverse of 2 / (3 * sqrt(3)).
You can check that this evaluates to the answer given in the question. Just multiply sqrt(3) to both the numerator and the numerator and you're there.
Hope it helps.
Let angle CAB be theta. Tangent theta is thus the ratio of length BC and length AB. Length AB is 3 * sqrt(3) and length BC is 2, as you wrote. Thus, theta is tangent inverse of 2 / (3 * sqrt(3)). I believe you're stuck here as you found the answer to be 30 - tangent inverse of 2 / (3 * sqrt(3)).
You can check that this evaluates to the answer given in the question. Just multiply sqrt(3) to both the numerator and the numerator and you're there.
Hope it helps.
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done
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Something like this would be good.
Date Posted:
4 years ago
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