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junior college 2 | H2 Maths
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Seo-jin Jeong
Seo-jin Jeong

junior college 2 chevron_right H2 Maths chevron_right Singapore

Hello! I would really appreciate if someone could help me with part (iii)! Thank you in advance!

Date Posted: 4 years ago
Views: 581
Eric Nicholas K
Eric Nicholas K
4 years ago
2x2 - 3xy + y2 = 5

Differentiating with respect to x,

4x - 3 [x dy/dx + y] + 2y dy/dx = 0
4x - 3x dy/dx - 3y + 2y dy/dx = 0
[2y - 3x] dy/dx = 3y - 4x
dy/dx = (3y - 4x) / (2y - 3x)

Suppose dy/dx = 0 (ie tangent is parallel to the horizontal x axis).

3y - 4x = 0
y = 4x/3

Substituting this to the original equation,

2x2 - 3x (4x/3) + (4x/3)^2 = 5
2x2 - 4x2 + 16x2/9 = 5
-2x2/9 = 5

Then,

x2 = -45/2

with no real roots and therefore there exists no point in the curve in which the tangent is parallel to the x axis.

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Rachel
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