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secondary 3 | E Maths
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I need help with part a. Please help!
Date Posted: 4 years ago
Views: 561
Basically, you should know that angle ACB = angle DAB = 90 deg. Thus, You can use the RHS similarity test here.
Question says that AB bisects Angle CBD. This means angle CBA = angle ABD. Let’s assign an algebraic term to these 2 angles. Let x = angle CBA = angle ABD.
Since we have 2 right angles triangles in ABC and DBA, we can use trigonometry.
For triangle DBA, we can deduce tan(x) = opp/adj = AD/AB = 9/22
For triangle ABC, we deduce that tan(x) = AC/BC
Since tan(x) = 9/22,
AC/BC = 9/22
Since the corresponding ratio of both sides of the triangles are equal, the RHS test is fulfilled and hence triangle ABC and DBA are similar.
Tip: recognise that RHS is also applicable to similarity.
Hope this helps!;)
Question says that AB bisects Angle CBD. This means angle CBA = angle ABD. Let’s assign an algebraic term to these 2 angles. Let x = angle CBA = angle ABD.
Since we have 2 right angles triangles in ABC and DBA, we can use trigonometry.
For triangle DBA, we can deduce tan(x) = opp/adj = AD/AB = 9/22
For triangle ABC, we deduce that tan(x) = AC/BC
Since tan(x) = 9/22,
AC/BC = 9/22
Since the corresponding ratio of both sides of the triangles are equal, the RHS test is fulfilled and hence triangle ABC and DBA are similar.
Tip: recognise that RHS is also applicable to similarity.
Hope this helps!;)
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done
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use properties of angles within a circle to derive which angles are equal
with 2 equal angles in the two triangles, it is proven that they are similar
with 2 equal angles in the two triangles, it is proven that they are similar
Date Posted:
4 years ago
How u know AB bisects angle CBD?
given in the question! :)
Oops sryy :) thank you!
no problem!!
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