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Question
secondary 3 | A Maths
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simultaneous
Date Posted: 4 years ago
Views: 298
2x - 3y = -1
x = (-1+3y)/2----(1)
Sub into the first equation,
2((-1+3y)/2)^2 - 3y^2 = 5
Solve this equation.
x = (-1+3y)/2----(1)
Sub into the first equation,
2((-1+3y)/2)^2 - 3y^2 = 5
Solve this equation.
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done
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clear
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Date Posted:
4 years ago
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