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primary 5 | Maths
| Whole Numbers
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Can someone help me with tbis question? Thank.you
3462
3462
Notice that the pattern repeats itself every 4 numbers.
9 divided by 4 leaves a remainder of 1. This remainder 1 corresponds to the first of the four-digit formation 3462, which is digit 3.
10 divided by 4 leaves a remainder of 2. This remainder 2 corresponds to the second of the four-digit formation 3462, which is digit 4.
11 divided by 4 leaves a remainder of 3. This remainder 3 corresponds to the third of the four-digit formation 3462, which is digit 6.
12 divided by 4 leaves no remainder. This can be thought of as a remainder of “4”. This remainder “4” corresponds to the fourth digit of the four-digit formation 3462, which is 2.
And so on.
So let’s say we wish to find the 100th number. 100 divided by 4 leaves no remainder, but for the purposes of this question we say a remainder “4”. This corresponds to the fourth digit, which is 2.
Therefore, we have the following.
427 divided by 4 is 106 with a remainder of 3.
This remainder of 3 corresponds to digit 6, so the 427th digit is 6.
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