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junior college 2 | H2 Maths
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Q1&2
Date Posted: 4 years ago
Views: 323
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Apologies … just realised that I have made a mistake in interpreting the question for part (iii). Have re-worked solution and posted amended solution below.
done
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for last part, you should also be able to get the answer using the binomial distribution function on your graphic calculator.
Date Posted:
4 years ago
done
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Amended part (iii) answer.
I am interpreting the question as asking for the number of new sub-committees where the husband and wife are not both together in the new sub-committee .
I am interpreting the question as asking for the number of new sub-committees where the husband and wife are not both together in the new sub-committee .
Date Posted:
4 years ago
alternatively,
select husband only = 1 x 7C5 = 21
select wife only = 1 x 7C5 = 21
not select couple = 7C6 = 7
total possible committees = 21+21+7 = 49
select husband only = 1 x 7C5 = 21
select wife only = 1 x 7C5 = 21
not select couple = 7C6 = 7
total possible committees = 21+21+7 = 49
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