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primary 6 | Maths
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Please help me solve the question.thank you
Date Posted: 6 years ago
Views: 383
I really need help
Do you know simultaneous equations? The only method I can think of as of now is via that.
Let x be the no. of companies & let y be the no. of tickets.
Equation (1)
4x = y + 20
because to give each of the companies 4 tickets each he still need another 20 more tickets to do so
Equation (2)
3x = y - 50
because to give each of the companies 3 tickets each he will have 50 tickets left
From the first equation, we can rearrange in such a way that x = y/4 +5
Substitute this new found equation into Equation 2:
3x = y - 50
so it becomes
3(y/4 + 5) = y - 50
y = 260 which is the no. of tickets!
Let x be the no. of companies & let y be the no. of tickets.
Equation (1)
4x = y + 20
because to give each of the companies 4 tickets each he still need another 20 more tickets to do so
Equation (2)
3x = y - 50
because to give each of the companies 3 tickets each he will have 50 tickets left
From the first equation, we can rearrange in such a way that x = y/4 +5
Substitute this new found equation into Equation 2:
3x = y - 50
so it becomes
3(y/4 + 5) = y - 50
y = 260 which is the no. of tickets!
See 1 Answer
done
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clear
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using grouping method to solve this type of question.
Date Posted:
6 years ago
Thank you
You're welcome
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