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Question
secondary 4 | E Maths
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Bmat math
A) 1, 2
B) 2, 3
C) 3,4
D) 4, 5
Let the first digit be a and second digit be a+1.
Substitute the combinations (A,B,C,D) into this equation.
a+ (fourth digit) = (a+1)* (third digit)
Option A (1,2)
a + 2 = (a+1) * 1
a + 2 = a+ 1 (Wrong)
Option B (2,3)
a + 3 = (a+1)*2
a+ 3 = 2a +2
a =1 (Correct answer)
Option C (3,4)
a+4 = (a+1) *3
a+ 4 = 3a +3
2a = 1
a= 0.5 (Wrong as it is an integer)
Option D (4,5)
a+ 5 = (a+1)*4
a+5 = 4a +4
3a = 1
a=1/3 (Wrong as it is an integer)
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