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Secondary 1 | Maths
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Second number: m - 7
Third number: m
Fourth number: m + 7
Fifth number: m + 14
Their sum is 5m (after simplification).
Since the sum of the numbers is at least 130,
5m >= 130
Dividing both sides (as you would for a regular equation),
m >= 26
Least m is 26.
But then, m is a multiple of 7.
Least m is 28.
Least value of largest number is 28 + 14 = 42.
Sorry, please correct me if im wrong.
Second number: m - 7
Third number: m
Fourth number: m + 7
Fifth number: m + 14
Their sum is 5m (after simplification).
Since the average of the numbers is at least 130, their total sum must at least be 650.
5m >= 650
Dividing both sides (as you would for a regular equation),
m >= 130
Least m is 130
But then, m is a multiple of 7.
Least m is 133.
Least value of largest number is 133 + 14 = 147.
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Better is “least m is 133” and “least value of fifth number is 147”.
In your case with 130 and 144, these are numbers separated by differences which are multiples of 7, but the five numbers themselves are not multiples of 7.