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secondary 4 | E Maths
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Date Posted: 5 years ago
Views: 270
sin θ = sin (180° - θ)
If sin θ = 0.723,
Basic angle θ = sin-¹(0.723)
≈ 46.303°
Since the angle in the triangle is obtuse,
Angle
= 180° - 46.303°
= 133.697°
= 133.7° (1 d.p)
If sin θ = 0.723,
Basic angle θ = sin-¹(0.723)
≈ 46.303°
Since the angle in the triangle is obtuse,
Angle
= 180° - 46.303°
= 133.697°
= 133.7° (1 d.p)
Kathy, you can continue to use the ASTC approach as always, just that angles in a triangle are limited to within 180 degrees (the first two quadrants equivalent).
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Hope this helps
Date Posted:
5 years ago
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