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secondary 3 | A Maths
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Date Posted: 4 years ago
Views: 209
15 > 30 - 6ln(t + 1)
6ln(t + 1) > 30 - 15
6ln(t + 1) > 15
ln (t + 1) > 15/6
t + 1 > e^(15/6)
t > e^(15/6) - 1
t > 11.182494
6ln(t + 1) > 30 - 15
6ln(t + 1) > 15
ln (t + 1) > 15/6
t + 1 > e^(15/6)
t > e^(15/6) - 1
t > 11.182494
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done
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clear
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We can’t exactly find a fixed value for t, but we can find a range of values for it.
Date Posted:
4 years ago
Thabks
Thank you
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