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primary 5 | Maths
| Area & Volume
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Can any teacher please guide me how to find area if rectangle ABCD? TQ!
Date Posted: 5 years ago
Views: 622
triangle CDF = 24
triangle CDF = 0.5 x CD x GD
so
0.5 x CD x GD = 24
CD x GD = 48
area of ABCD = CD x AD
= CD x (AG + GD)
= CD x (GD + GD)
= CD x 2 GD
= 2 x CD x GD
= 2 x 48
= 96 cm²
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triangle CDF = 0.5 x CD x GD
so
0.5 x CD x GD = 24
CD x GD = 48
area of ABCD = CD x AD
= CD x (AG + GD)
= CD x (GD + GD)
= CD x 2 GD
= 2 x CD x GD
= 2 x 48
= 96 cm²
.
.
.
TQ teacher
welcome
Teacher any easier method
you can just use 24 x 4 = 96. This is because Area of triangle CDF= Area of triangle CDG. Since AG = DG, there are two similar rectangles inside of ABCD. Area of triangle CDG = area of half of the rectangle. Thus, you just need to 24 x4 to find the whole of ABCD.
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