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secondary 4 | A Maths
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Pls help with q2 thanks!
Date Posted: 4 years ago
Views: 204
x(2 - x) = 3
since α is a root of the equation,
α(2 - α) = 3
Multiply both sides by (2 + α),
α(2 - α)(2 + α) = 3(2 + α)
α(2² - α²) = 6 + 3α
(using property a² - b² = (a + b)(a - b))
4α - α³ = 6 + 3α
α³ = a - 6
(Last edit 12.08pm)
since α is a root of the equation,
α(2 - α) = 3
Multiply both sides by (2 + α),
α(2 - α)(2 + α) = 3(2 + α)
α(2² - α²) = 6 + 3α
(using property a² - b² = (a + b)(a - b))
4α - α³ = 6 + 3α
α³ = a - 6
(Last edit 12.08pm)
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done
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You can also multiply the expression by other linear terms such a - 2, but then the term in a2 survives and you will need to use the original equation to obtain a2 in terms of other terms so that the a2 gets substituted away.
Date Posted:
4 years ago
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