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secondary 3 | A Maths
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Please help me with question 4b
Date Posted: 4 years ago
Views: 258
Good evening Sophie! I will write this down for you later if no one has done them yet.
Thanks Eric
y = (ax2 + bx + c)^2
We bring down the power 2 into the front, then reduce the power by 1, then multiply by the differential of the “chain” inside the bracket
dy/dx = 2 times (ax2 + bx + c)^1 times (2ax + b)
We bring down the power 2 into the front, then reduce the power by 1, then multiply by the differential of the “chain” inside the bracket
dy/dx = 2 times (ax2 + bx + c)^1 times (2ax + b)
I need to use chain and quotient to find the answer, right?
Chain only, in fact.
Oh ok
See 1 Answer
done
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Good evening Sophie! Here are my workings for this question.
Date Posted:
4 years ago
Thank you
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