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primary 5 | Maths
| Angles & Geometry
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Date Posted: 4 years ago
Views: 357
Ans = 180
U need to know angle S+U+W+X+Q=540
a+c+X=180
b+d+Q =180
c+e+S=180
c = U+W-180
U need to know angle S+U+W+X+Q=540
a+c+X=180
b+d+Q =180
c+e+S=180
c = U+W-180
Angle TUS = angle UYR + angle URY
= angle d + angle a
(Exterior angle = sum of two interior opposite angles)
Angle TSU = angle SPU + angle SUP
= angle e + angle c
(Same reasoning)
Sum of angles in triangle TSU = 180°
Sum of angles in triangle TSU also
= Angle TSU + angle TUS + angle SUT
= angle e + angle c + angle d + a + angle b
So,
angle e + angle c + angle d + a + angle b
= 180°
You can also do the same but with the other 4 outside triangles
= angle d + angle a
(Exterior angle = sum of two interior opposite angles)
Angle TSU = angle SPU + angle SUP
= angle e + angle c
(Same reasoning)
Sum of angles in triangle TSU = 180°
Sum of angles in triangle TSU also
= Angle TSU + angle TUS + angle SUT
= angle e + angle c + angle d + a + angle b
So,
angle e + angle c + angle d + a + angle b
= 180°
You can also do the same but with the other 4 outside triangles
See 1 Answer
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Unbelievable is P5 question ?
Hope this helps
Hope this helps
Date Posted:
4 years ago
Thank you
Thanks
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