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secondary 2 | Maths
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Chapter : Simultaneous Linear Equations
Date Posted: 4 years ago
Views: 233
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Hope this helps
Date Posted:
4 years ago
Thank you so much
Kate: Father : Age difference (different must be same, age different will not change throughout all the age)
In 5 years time
Kate: Father : Age difference = 1:3:2
Kate: Father : Age difference = 5:15:10
4 years ago
Kate: Father : Age difference = 1:6:5
Kate: Father : Age difference = 2:12:10
Now, the age different is same = 10
Kate 5u-2u = 5+4
3u=9
u= 3
In 5 years time
Kate: Father : Age difference
5u:15u
Total age = 20u
= 20 x 3
= 60
Therefore, their total age now
= 60-10 ( 5 years each)
= 50.
Mean Kate 10 years old , his Father is 40 years old.
Hope this helps
In 5 years time
Kate: Father : Age difference = 1:3:2
Kate: Father : Age difference = 5:15:10
4 years ago
Kate: Father : Age difference = 1:6:5
Kate: Father : Age difference = 2:12:10
Now, the age different is same = 10
Kate 5u-2u = 5+4
3u=9
u= 3
In 5 years time
Kate: Father : Age difference
5u:15u
Total age = 20u
= 20 x 3
= 60
Therefore, their total age now
= 60-10 ( 5 years each)
= 50.
Mean Kate 10 years old , his Father is 40 years old.
Hope this helps
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Secondary level. Use algebra method ya. Hope this helps
Date Posted:
4 years ago
Thank you so much
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