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Question
secondary 3 | A Maths
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trigonometry
Date Posted: 4 years ago
Views: 210
(a)
tan² θ - sin² θ
= sin² θ (1/cos² θ - 1)
= sin² θ (sec² θ - 1)
since sec² θ = tan² θ + 1
sin² θ (sec² θ - 1)
= sin² θ tan² θ (proved)
tan² θ - sin² θ
= sin² θ (1/cos² θ - 1)
= sin² θ (sec² θ - 1)
since sec² θ = tan² θ + 1
sin² θ (sec² θ - 1)
= sin² θ tan² θ (proved)
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First part
Date Posted:
4 years ago
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Part two
Date Posted:
4 years ago
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